5c^2+13c=28

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Solution for 5c^2+13c=28 equation:


Simplifying
5c2 + 13c = 28

Reorder the terms:
13c + 5c2 = 28

Solving
13c + 5c2 = 28

Solving for variable 'c'.

Reorder the terms:
-28 + 13c + 5c2 = 28 + -28

Combine like terms: 28 + -28 = 0
-28 + 13c + 5c2 = 0

Factor a trinomial.
(-4 + -1c)(7 + -5c) = 0

Subproblem 1

Set the factor '(-4 + -1c)' equal to zero and attempt to solve: Simplifying -4 + -1c = 0 Solving -4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1c = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1c = 0 + 4 -1c = 0 + 4 Combine like terms: 0 + 4 = 4 -1c = 4 Divide each side by '-1'. c = -4 Simplifying c = -4

Subproblem 2

Set the factor '(7 + -5c)' equal to zero and attempt to solve: Simplifying 7 + -5c = 0 Solving 7 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -5c = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -5c = 0 + -7 -5c = 0 + -7 Combine like terms: 0 + -7 = -7 -5c = -7 Divide each side by '-5'. c = 1.4 Simplifying c = 1.4

Solution

c = {-4, 1.4}

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